Given two numbers, if we subtract half the smaller number from each number, the result with the larger number is three times as large as the result with the smaller number. How many times is the larger number as large as the smaller number?
This is my reasoning :- Let x be the larger number, y be the smaller number. x - y/2 = 3y/2 x = 2y So the larger number is twice the size of the smaller number.
This is my reasoning :- Let x be the larger number, y be the smaller number. x - y/2 = 3y/2 x = 2y So the larger number is twice the size of the smaller number.
4 Comments:
The larger number is twice that of the smaller number.
This is my reasoning :-
Let x be the larger number, y be the smaller number.
x - y/2 = 3y/2
x = 2y
So the larger number is twice the size of the smaller number.
This is my reasoning :-
Let x be the larger number, y be the smaller number.
x - y/2 = 3y/2
x = 2y
So the larger number is twice the size of the smaller number.
This is great info to know.
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