Mathematical Verse
This is a mathematical poem from India. It's quite easy to solve once you get the hang of it :-
O beautiful maiden with beaming eyes, tell me,
Since you understand the method of inversion,
What number multiplied by 2,
Then increased by three quarters of the product,
Then divided by seven,
Then diminished by one third of the result,
Then multiplied by itself,
Then diminished by 52,
Whose square root is then extracted,
Before 8 is added and then divided by 10,
Gives the final result of 2?
Answers in the comments. :)
posted by steven | 5:45 AM
5 Comments:
It's not 42. :)
The answer is 28.
2 * 10 = 20
20 - 8 = 12
12 squared = 144
144 + 52 = 196
sqrt 196 = 14
3/2 * 14 = 21
21 * 7 = 147
4/7 * 147 = 84
84/3 = 28
QED!
Steve, why 84/3?
I also go with 42 (assuming, as Sean said, that this is a straight chain without semantic tricks).
Ray
Looks like I committed a typo (typing 2 instead of 3). 28 is the answer to the puzzle as worded. Sorry about that. - steven
Pls. ignore previous comment.
Looks like I committed a typo (typing 2 instead of 3). 42 is the answer to the puzzle as worded. Sorry about that. - steven
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