### Mathematical Verse

This is a mathematical poem from India. It's quite easy to solve once you get the hang of it :-

O beautiful maiden with beaming eyes, tell me,

Since you understand the method of inversion,

What number multiplied by 2,

Then increased by three quarters of the product,

Then divided by seven,

Then diminished by one third of the result,

Then multiplied by itself,

Then diminished by 52,

Whose square root is then extracted,

Before 8 is added and then divided by 10,

Gives the final result of 2?

Answers in the comments. :)

## 6 Comments:

The answer I have is 42, assuming no tricks. However, if the line "multiplied by itself" means multiplied by the original number, then I'm ridiculously off base. In which case, it's my girlfriend's fault.

It's not 42. :)

The answer is 28.

2 * 10 = 20

20 - 8 = 12

12 squared = 144

144 + 52 = 196

sqrt 196 = 14

3/2 * 14 = 21

21 * 7 = 147

4/7 * 147 = 84

84/3 = 28

QED!

Steve, why 84/3?

I also go with 42 (assuming, as Sean said, that this is a straight chain without semantic tricks).

Ray

Looks like I committed a typo (typing 2 instead of 3). 28 is the answer to the puzzle as worded. Sorry about that. - steven

Pls. ignore previous comment.

Looks like I committed a typo (typing 2 instead of 3). 42 is the answer to the puzzle as worded. Sorry about that. - steven

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