Saturday, October 30, 2004

Mathematical Verse

This is a mathematical poem from India. It's quite easy to solve once you get the hang of it :-

O beautiful maiden with beaming eyes, tell me,
Since you understand the method of inversion,
What number multiplied by 2,
Then increased by three quarters of the product,
Then divided by seven,
Then diminished by one third of the result,
Then multiplied by itself,
Then diminished by 52,
Whose square root is then extracted,
Before 8 is added and then divided by 10,
Gives the final result of 2?

Answers in the comments. :)

6 Comments:

Blogger Sean said...

The answer I have is 42, assuming no tricks. However, if the line "multiplied by itself" means multiplied by the original number, then I'm ridiculously off base. In which case, it's my girlfriend's fault.

October 31, 2004 at 3:59 PM  
Anonymous Anonymous said...

It's not 42. :)

November 2, 2004 at 11:10 PM  
Blogger steven said...

The answer is 28.

2 * 10 = 20
20 - 8 = 12
12 squared = 144
144 + 52 = 196
sqrt 196 = 14
3/2 * 14 = 21
21 * 7 = 147
4/7 * 147 = 84
84/3 = 28

QED!

November 6, 2004 at 5:29 AM  
Anonymous Anonymous said...

Steve, why 84/3?

I also go with 42 (assuming, as Sean said, that this is a straight chain without semantic tricks).

Ray

December 17, 2004 at 4:41 AM  
Anonymous Anonymous said...

Looks like I committed a typo (typing 2 instead of 3). 28 is the answer to the puzzle as worded. Sorry about that. - steven

March 21, 2005 at 1:10 PM  
Anonymous Anonymous said...

Pls. ignore previous comment.

Looks like I committed a typo (typing 2 instead of 3). 42 is the answer to the puzzle as worded. Sorry about that. - steven

March 21, 2005 at 1:11 PM  

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